Vertical Motion Challenge

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Quiz on vertical motion problems

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Aimee

Philippines

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Vertical Motion Challenge


Vertical Motion ChallengeVersion en ligne Quiz on vertical motion problems par Aimee 1 A ball is dropped from rest from a height of 19.6 m. How long to reach the ground? a 1.5 s b 2.0 s c 1.0 s d 2.5 s 2 A stone is dropped from a bridge and reaches the water after 3.0 s. What is the height of the bridge? a 49.0 m b 39.2 m c 54.9 m d 44.1 m 3 A ball is thrown vertically upward at 19.6 m/s. What is its velocity at the highest point? a 4.9 m/s b 19.6 m/s c 9.8 m/s d 0.0 m/s 4 A ball is thrown upward at 19.6 m/s. What maximum height will it reach? a 29.4 m b 19.6 m c 14.7 m d 9.8 m 5 A ball is thrown upward at 24.5 m/s. What will its velocity be after 1.5 s? a 14.7 m/s downward b 14.7 m/s upward c 9.8 m/s upward d 9.8 m/s downward 6 A ball is thrown upward at 19.6 m/s. At what two times will it be 14.7 m above its starting point? a 1.0 s and 2.0 s b 1.5 s and 2.5 s c 1.0 s and 3.0 s d 2.0 s and 3.0 s 7 A stone is thrown downward at 5.0 m/s from a height of 30 m. Approximately how long to reach the ground? a 2.5 s b 2.2 s c 1.5 s d 2.0 s 8 A ball is thrown upward from the top of a 20 m building with 14.7 m/s. What is the maximum height above ground? a 35.0 m b 25.5 m c 30.0 m d 31.0 m 9 A ball is thrown upward. After 2.0 s, its velocity is 4.6 m/s downward. What was its initial velocity? a 17.0 m/s b 19.6 m/s c 15.0 m/s d 14.2 m/s 10 A stone is thrown vertically upward and reaches a maximum height of 45 m. What was its initial velocity? a 29.7 m/s b 24.5 m/s c 19.6 m/s d 39.6 m/s Feedback 1 From vertical motion equations with g=9.8 m/s2. Source: Directions.6a82947110109.docx. 2 Uses s=0.5 g t^2 with g=9.8 m/s2. Source: Directions.6a82947110109.docx. 3 Velocity at top is zero. Source: Directions.6a82947110109.docx. 4 Use v^2 = u^2 - 2 g h with v=0. Source: Directions.6a82947110109.docx. 5 v = u - g t ; g=9.8 m/s2. Source: Directions.6a82947110109.docx. 6 Solve s(t)=14.7 with s= u t - 0.5 g t^2. Source: Directions.6a82947110109.docx. 7 Use s ≈ ut + 0.5 g t^2 with downward as positive. Source: Directions.6a82947110109.docx. 8 Height gain = u^2/(2g) ≈ (14.7^2)/(19.6) ≈ 11.0 m. Total ~31.0 m. Source: Directions.6a82947110109.docx. 9 Using v = u - g t with downward positive. Source: Directions.6a82947110109.docx. 10 From v^2 = u^2 - 2 g h with h=45 m. Source: Directions.6a82947110109.docx.

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Vertical Motion Challenge

Test

À propos de cette activité

Créé par

Téléchargez la version pour jouer sur papier

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Vertical Motion ChallengeVersion en ligne

par Aimee

A ball is dropped from rest from a height of 19.6 m. How long to reach the ground?

A stone is dropped from a bridge and reaches the water after 3.0 s. What is the height of the bridge?

A ball is thrown vertically upward at 19.6 m/s. What is its velocity at the highest point?

A ball is thrown upward at 19.6 m/s. What maximum height will it reach?

A ball is thrown upward at 24.5 m/s. What will its velocity be after 1.5 s?

A ball is thrown upward at 19.6 m/s. At what two times will it be 14.7 m above its starting point?

A stone is thrown downward at 5.0 m/s from a height of 30 m. Approximately how long to reach the ground?

A ball is thrown upward from the top of a 20 m building with 14.7 m/s. What is the maximum height above ground?

A ball is thrown upward. After 2.0 s, its velocity is 4.6 m/s downward. What was its initial velocity?

A stone is thrown vertically upward and reaches a maximum height of 45 m. What was its initial velocity?

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