Energy Essentials Quiz

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Energy concepts and calculations

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Matangi Mathu

India

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Energy Essentials Quiz


Energy Essentials QuizVersion en ligne Energy concepts and calculations par Matangi Mathu 1 A 5 kg block is lifted 2 m. What is the work done against gravity? (g = 9.8 m/s^2) a 10 J b 196 J c 490 J d 98 J 2 A 3 kg mass is released from rest and falls 4 m. What is its potential energy lost (ignore air resistance)? a 49 J b 117.6 J c 12 J d 235 J 3 If a 2 kg object gains 20 J of kinetic energy, what is its new velocity? (initially at rest) a v = 2 m/s b v = 6 m/s c v = √(40) ≈ 6.32 m/s d v = √(2×20/2) = √20 ≈ 4.47 m/s 4 A 10 N force moves an object 3 m in the direction of the force. What is the work done? a 30 J b 33 J c 13 J d 3 J 5 Which quantity remains constant in a frictionless system when only conservative forces act? a Work rate b Power c Kinetic energy d Mechanical energy 6 Power is defined as the rate of doing work. Which unit is correct for power? a Watt (W) b Newton (N) c Meter (m) d Joule (J) 7 A 4 kg object is raised by 5 m. What is its potential energy at the top (take ground as zero)? a U = 40 J b U = 196 J c U = 400 J d U = 980 J 8 If kinetic energy doubles while mass remains the same, what happens to velocity? a Velocity halves b Velocity increases by √2 times c Velocity doubles d Velocity stays the same 9 A machine does 150 J of work in 15 s. What is its power output? a 1.0 W b 0.1 W c 1500 W d 10 W 10 Two equal masses slide frictionlessly down different heights. Which mass has greater KE at bottom? a Both have the same KE if heights are equal; otherwise the one from greater height b Neither has KE c The heavier mass always has more KE d The lighter mass always has more KE Feedback 1 Work done against gravity W = m g h = 5×9.8×2 = 98 J. 2 ΔU = m g h = 3×9.8×4 = 117.6 J. 3 KE = 1/2 m v^2, so v = √(2KE/m) = √(40/2) = √20 ≈ 4.47 m/s. 4 W = Fd cosθ, here θ=0°, so W = 10×3 = 30 J. 5 In the absence of non-conservative forces, total mechanical energy is conserved. 6 P = W/t ; unit is joule per second = watt. 7 U = m g h = 4×9.8×5 = 196 J. 8 KE ∝ v^2, so doubling KE means v × √2. 9 P = W/t = 150/15 = 10 W. 10 For equal masses, KE at bottom depends on height; m cancels in mgh = KE. If heights equal, KE equal.

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Energy Essentials Quiz

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À propos de cette activité

Créé par

Téléchargez la version pour jouer sur papier

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Energy Essentials QuizVersion en ligne

par Matangi Mathu

A 5 kg block is lifted 2 m. What is the work done against gravity? (g = 9.8 m/s^2)

A 3 kg mass is released from rest and falls 4 m. What is its potential energy lost (ignore air resistance)?

If a 2 kg object gains 20 J of kinetic energy, what is its new velocity? (initially at rest)

A 10 N force moves an object 3 m in the direction of the force. What is the work done?

Which quantity remains constant in a frictionless system when only conservative forces act?

Power is defined as the rate of doing work. Which unit is correct for power?

A 4 kg object is raised by 5 m. What is its potential energy at the top (take ground as zero)?

If kinetic energy doubles while mass remains the same, what happens to velocity?

A machine does 150 J of work in 15 s. What is its power output?

Two equal masses slide frictionlessly down different heights. Which mass has greater KE at bottom?

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