Stoichiometry Quick Fire

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A fast true/false quiz on stoichiometry concepts.

Créé par

Havana Rooseleer

United Arab Emirates

Téléchargez la version pour jouer sur papier

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1	Havana Rooseleer 3 Décembre 2025	% 88	02:27

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Stoichiometry Quick Fire


Stoichiometry Quick FireVersion en ligne A fast true/false quiz on stoichiometry concepts. par Havana Rooseleer 1 H2 + C -> CH4 is a reaction where oxygen is produced as a product. Yes No 2 If you know the mass and the volume of a solution, you cannot determine its concentration. Yes No 3 To find moles from concentration and volume, use n = C × V (with V in liters). Yes No 4 In the reaction between 10.0 g Na and 10.0 g Cl2, chlorine is in excess. Yes No 5 Moles cannot be calculated from information about elementary entities, only from mass. Yes No 6 One mole of any substance always contains exactly 1000 molecules. Yes No 7 To convert between moles and particles, multiply moles by Avogadro’s number: N = n × Na. Yes No 8 Oxygen is the limiting reagent when 1 g carbon reacts with 1 g oxygen to form CO2. Yes No 9 One mole contains 6.02 x 10^23 particles, a value known as Avogadro's number. Yes No 10 In the burger analogy, the limiting reagent is the ingredient you have the most of. Yes No 11 The formula mass is always measured in kilograms per mole. Yes No 12 The number of moles from mass is calculated as n = mass / Mr (molar/formula mass). Yes No 13 Avogadro’s number is 6.02 × 10^21, not 10^23. Yes No 14 In the methane formation example, carbon is the limiting reagent when 10.0 g H2 reacts with 5.00 g C to form CH4. Yes No 15 The volume method can determine the limiting reagent for all gas reactions, regardless of conditions. Yes No 16 Hydrogen is the limiting reagent when 0.38 g H2 reacts with 3.20 g O2. Yes No 17 Molar mass for elements equals the atomic mass on the periodic table, while for compounds it equals the formula mass. Yes No

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Stoichiometry Quick Fire

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À propos de cette activité

Créé par

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Stoichiometry Quick FireVersion en ligne

par Havana Rooseleer

H2 + C -> CH4 is a reaction where oxygen is produced as a product.

If you know the mass and the volume of a solution, you cannot determine its concentration.

To find moles from concentration and volume, use n = C × V (with V in liters).

In the reaction between 10.0 g Na and 10.0 g Cl2, chlorine is in excess.

Moles cannot be calculated from information about elementary entities, only from mass.

One mole of any substance always contains exactly 1000 molecules.

To convert between moles and particles, multiply moles by Avogadro’s number: N = n × Na.

Oxygen is the limiting reagent when 1 g carbon reacts with 1 g oxygen to form CO2.

One mole contains 6.02 x 10^23 particles, a value known as Avogadro's number.

In the burger analogy, the limiting reagent is the ingredient you have the most of.

The formula mass is always measured in kilograms per mole.

The number of moles from mass is calculated as n = mass / Mr (molar/formula mass).

Avogadro’s number is 6.02 × 10^21, not 10^23.

In the methane formation example, carbon is the limiting reagent when 10.0 g H2 reacts with 5.00 g C to form CH4.

The volume method can determine the limiting reagent for all gas reactions, regardless of conditions.

Hydrogen is the limiting reagent when 0.38 g H2 reacts with 3.20 g O2.

Molar mass for elements equals the atomic mass on the periodic table, while for compounds it equals the formula mass.