Icon Créer jeu Créer jeu

Mastering SQL Window Functions

Compléter

Drills to master window functions in SQL

Téléchargez la version pour jouer sur papier

0 fois fait

Créé par

United States

Top 10 résultats

Il n'y a toujours pas de résultats pour ce jeu. Soyez le premier à apparaître dans le classement! pour vous identifier.
Créez votre propre jeu gratuite à partir de notre créateur de jeu
Affrontez vos amis pour voir qui obtient le meilleur score dans ce jeu

Top Jeux

  1. temps
    but
  1. temps
    but
temps
but
temps
but
 
game-icon

Compléter

Mastering SQL Window FunctionsVersion en ligne

Drills to master window functions in SQL

par Good Sam
1

amount SUM ORDER SELECT FROM AS sale_date OVER sale_date sales BY running_total amount

Problem 1 : Calculate Running Total
Question : You have a table sales ( sale_date DATE , amount DECIMAL ) . Write a SQL query to calculate a running total of amount , ordered by sale_date .

Solution :

, ,
( ) ( )
;

2

as CURRENT amount FOLLOWING sales FROM AND UNBOUNDED moving_avg BY BY running_total ROW AND BETWEEN as ROWS OVER AND SUM ROWS as ORDER AVG FROM sales PRECEDING sale_date ORDER sale_date BY ROWS sale_date OVER amount SELECT 6 3 amount AVG ORDER amount SELECT OVER sales ROW sale_date sales BY AND UNBOUNDED BETWEEN BETWEEN sale_date sale_date moving_avg OVER BY CURRENT current_avg ORDER SELECT ROW FROM ROWS amount CURRENT BETWEEN amount sales FROM 3 amount PRECEDING sum_to_end SELECT amount CURRENT CURRENT SUM AVG ROW BETWEEN AND sale_date OVER PRECEDING as amount FOLLOWING FROM ROWS ORDER ROW sale_date as sale_date

Problem 2 : Calculate Moving Average
Question : Calculate a 7 - day moving average of sales from the sales table .

Solution :

, ,
( ) ( )
;

Example 2 : Fixed Range with Both PRECEDING and FOLLOWING

, ,
( ) ( )
;

This calculates the average amount using a window that includes three rows before , the current row , and three rows after the current row .

Example 3 : From Start of Data to Current Row
, ,
( ) ( )
;

This query computes a running total starting from the first row in the partition or result set up to the current row .

Example 4 : Current Row to End of Data
SELECT sale_date , amount ,
( ) ( )
;

This sums the amount from the current row to the last row of the partition or result set .

Example 5 : Current Row Only
, ,
( ) ( )
;

This calculates the average of just the current row's amount , which effectively returns the amount itself .

3

FROM id OVER customers AS total_purchases ORDER total_purchases SELECT rank name BY DESC RANK

Problem 3 : Rank Customers by Sales

Question : From a table customers ( id INT , name VARCHAR , total_purchases DECIMAL ) , rank customers based on their total_purchases in descending order .

Solution :

, , ,
( ) ( )
;
Explanation : RANK ( ) assigns a unique rank to each row , with gaps in the ranking for ties , based on the total_purchases in descending order .

4

AS ROW_NUMBER() OVER sale_date row_num ORDER sale_date SELECT FROM sales BY amount

Problem 4 : Row Numbering

Question : Assign a unique row number to each sale in the sales table ordered by sale_date .

Solution :

, ,
( )
;

Explanation : ROW_NUMBER ( ) generates a unique number for each row , starting at 1 , based on the ordering of sale_date .

5

SELECT first_purchase customer_id AS MIN purchase_date FROM BY customer_id purchases PARTITION OVER

Problem 5 : Find the First Purchase Date for Each Customer
Question : Given a table purchases ( customer_id INT , purchase_date DATE ) , write a SQL query to find the first purchase date for each customer .

Solution :

, ( ) ( )
;

Explanation : MIN ( ) window function is used here , partitioned by customer_id so that the minimum purchase date is calculated for each customer separately .

6

change_in_amount amount ORDER sale_date previous_day_amount amount amount BY LAG ORDER OVER sale_date sales_data AS AS FROM sale_date OVER LAG BY 1 1 amount SELECT

The LAG function is very useful in scenarios where you need to compare successive entries or calculate differences between them . For example , calculating day - over - day sales changes :


SELECT sale_date ,
amount ,
LAG ( amount , 1 ) OVER ( ORDER BY sale_date ) AS previous_day_amount ,
amount - LAG ( amount , 1 ) OVER ( ORDER BY sale_date ) AS change_in_amount
FROM sales_data ;



,
,
( , ) ( ) ,
- ( , ) ( )
;

In this query , the change_in_amount field computes the difference in sales between consecutive days . If the LAG function references a row that doesn't exist ( e . g . , the first row in the dataset ) , it will return NULL unless a default value is specified .


The LAG window function in SQL is used to access data from a previous row in the same result set without the need for a self - join . It's a part of the SQL window functions that provide the ability to perform calculations across rows that are related to the current row . LAG is particularly useful for comparisons between records in ordered data .

How LAG Works :
LAG takes up to three arguments :

Expression : The column or expression you want to retrieve from a preceding row .
Offset : An optional integer specifying how many rows back from the current row the function should look . If not specified , the default is 1 , meaning the immediate previous row .
Default : An optional argument that provides a default value to return if the LAG function attempts to go beyond the first row of the dataset .
Syntax :
LAG ( expression , offset , default ) OVER ( [ PARTITION BY partition_expression ] ORDER BY sort_expression )