Icon Créer jeu Créer jeu

Mastering SQL Window Functions

Compléter

Drills to master window functions in SQL

Téléchargez la version pour jouer sur papier

0 fois fait

Créé par

United States

Top 10 résultats

Il n'y a toujours pas de résultats pour ce jeu. Soyez le premier à apparaître dans le classement! pour vous identifier.
Créez votre propre jeu gratuite à partir de notre créateur de jeu
Affrontez vos amis pour voir qui obtient le meilleur score dans ce jeu

Top Jeux

  1. temps
    but
  1. temps
    but
temps
but
temps
but
 
game-icon

Compléter

Mastering SQL Window FunctionsVersion en ligne

Drills to master window functions in SQL

par Good Sam
1

running_total FROM amount AS sale_date sales BY SELECT OVER sale_date amount ORDER SUM

Problem 1 : Calculate Running Total
Question : You have a table sales ( sale_date DATE , amount DECIMAL ) . Write a SQL query to calculate a running total of amount , ordered by sale_date .

Solution :

, ,
( ) ( )
;

2

sale_date BETWEEN AND AND sale_date BY ROWS as AND FROM FOLLOWING FROM ROWS BETWEEN BY amount BY CURRENT ORDER ROW amount ROW sales FOLLOWING amount SUM OVER UNBOUNDED 6 sale_date ROWS OVER CURRENT CURRENT moving_avg ORDER SELECT ROW sales OVER SELECT CURRENT moving_avg AVG sale_date sum_to_end ROWS AVG as OVER PRECEDING amount sale_date amount sale_date ORDER FROM sale_date BETWEEN ORDER ROW sale_date FROM amount sales running_total sales UNBOUNDED 3 3 BETWEEN amount SUM BETWEEN AND FROM AND BY ROW PRECEDING sale_date amount ROWS CURRENT sales as SELECT current_avg as SELECT as OVER AVG ORDER PRECEDING amount BY

Problem 2 : Calculate Moving Average
Question : Calculate a 7 - day moving average of sales from the sales table .

Solution :

, ,
( ) ( )
;

Example 2 : Fixed Range with Both PRECEDING and FOLLOWING

, ,
( ) ( )
;

This calculates the average amount using a window that includes three rows before , the current row , and three rows after the current row .

Example 3 : From Start of Data to Current Row
, ,
( ) ( )
;

This query computes a running total starting from the first row in the partition or result set up to the current row .

Example 4 : Current Row to End of Data
SELECT sale_date , amount ,
( ) ( )
;

This sums the amount from the current row to the last row of the partition or result set .

Example 5 : Current Row Only
, ,
( ) ( )
;

This calculates the average of just the current row's amount , which effectively returns the amount itself .

3

SELECT id DESC BY rank ORDER name FROM RANK total_purchases total_purchases AS customers OVER

Problem 3 : Rank Customers by Sales

Question : From a table customers ( id INT , name VARCHAR , total_purchases DECIMAL ) , rank customers based on their total_purchases in descending order .

Solution :

, , ,
( ) ( )
;
Explanation : RANK ( ) assigns a unique rank to each row , with gaps in the ranking for ties , based on the total_purchases in descending order .

4

FROM sale_date ORDER SELECT AS amount row_num sales BY ROW_NUMBER() OVER sale_date

Problem 4 : Row Numbering

Question : Assign a unique row number to each sale in the sales table ordered by sale_date .

Solution :

, ,
( )
;

Explanation : ROW_NUMBER ( ) generates a unique number for each row , starting at 1 , based on the ordering of sale_date .

5

purchases first_purchase FROM customer_id customer_id BY OVER SELECT MIN PARTITION AS purchase_date

Problem 5 : Find the First Purchase Date for Each Customer
Question : Given a table purchases ( customer_id INT , purchase_date DATE ) , write a SQL query to find the first purchase date for each customer .

Solution :

, ( ) ( )
;

Explanation : MIN ( ) window function is used here , partitioned by customer_id so that the minimum purchase date is calculated for each customer separately .

6

1 AS AS OVER sale_date sale_date amount BY change_in_amount FROM amount ORDER 1 LAG OVER previous_day_amount SELECT amount BY amount ORDER sales_data LAG sale_date

The LAG function is very useful in scenarios where you need to compare successive entries or calculate differences between them . For example , calculating day - over - day sales changes :


SELECT sale_date ,
amount ,
LAG ( amount , 1 ) OVER ( ORDER BY sale_date ) AS previous_day_amount ,
amount - LAG ( amount , 1 ) OVER ( ORDER BY sale_date ) AS change_in_amount
FROM sales_data ;



,
,
( , ) ( ) ,
- ( , ) ( )
;

In this query , the change_in_amount field computes the difference in sales between consecutive days . If the LAG function references a row that doesn't exist ( e . g . , the first row in the dataset ) , it will return NULL unless a default value is specified .


The LAG window function in SQL is used to access data from a previous row in the same result set without the need for a self - join . It's a part of the SQL window functions that provide the ability to perform calculations across rows that are related to the current row . LAG is particularly useful for comparisons between records in ordered data .

How LAG Works :
LAG takes up to three arguments :

Expression : The column or expression you want to retrieve from a preceding row .
Offset : An optional integer specifying how many rows back from the current row the function should look . If not specified , the default is 1 , meaning the immediate previous row .
Default : An optional argument that provides a default value to return if the LAG function attempts to go beyond the first row of the dataset .
Syntax :
LAG ( expression , offset , default ) OVER ( [ PARTITION BY partition_expression ] ORDER BY sort_expression )