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Naming Compounds

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Naming and Writing the formula for ionic and covalent compounds

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HS1
Chemistry
molecular formula
ionic compounds
covalent compounds
naming
 Âge recommandé: 14 ans
5 fois fait

Créé par

Eric D Norman
Eric D Norman
United States

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Naming CompoundsVersion en ligne

Naming and Writing the formula for ionic and covalent compounds

par Eric D Norman
1

An Ionic Compound is between _________

Select one or more answers

2

Which answer below represents the oxidation state of aluminum then oxygen?

3

Which answer is the molecular formula for aluminum oxide?

4

You try! Which answer below is the molecular formula for potassium oxide?

5

In naming ionic compounds with transition metals, the roman numeral tells you the ___________.

Written answer

6

Which of the following answers below is the molecular formula for iron (III) oxide?

7

You try! Write the molecular formula for nickel (I) oxide.

Written answer

8

The prefix hepta- stands for...

9

Covalent compounds consists of . . .

10

What is the molecular formula for diphosphorus pentoxide?

11

You try! What is the molecular formula for trinitrogen hexasulfide

Written answer

12

Which of the answers below is the formula name for N3O6?

13

You try! Write the formula name for P3Cl5.

Written answer

Explanation

Remember that ionic compounds consist of metal and nonmetal and covalent compounds consist of two nonmetals. You can determine a metal from a nonmetal by looking at your periodic table. Most periodic tables will have a key indicating the type of elements.

Remember: All elements in Group 1 have an oxidation number of +1; Group 2 = +2; Group 13 = +3; Group 15 = -3; Group 16 = -2 and Group 17 = -1

Remember: All elements in Group 1 have an oxidation number of +1; Group 2 = +2; Group 13 = +3; Group 15 = -3; Group 16 = -2 and Group 17 = -1

element symbol for potassium is K; the oxidation states: K+1 and O-2; you use the swap technique and you have 2 K atoms and 1 O atom. So the formula would be K2O

As a reminder: Roman Numeral I = 1 Roman Numeral II = 2 Roman Numeral III = 3 Roman Numeral IV = 4 Roman Numeral V = 5

As a reminder: Roman Numeral I = 1 Roman Numeral II = 2 Roman Numeral III = 3 Roman Numeral IV = 4 Roman Numeral V = 5

As a reminder: Roman Numeral I = 1 Roman Numeral II = 2 Roman Numeral III = 3 Roman Numeral IV = 4 Roman Numeral V = 5

Copy the following if you did not get it off of the video: mono- = 1 di- = 2 tri- = 3 tetra- = 4 penta- = 5 hexa- = six hepa- = 7 octa- = 8 nona- = 9 deca- = 10

Copy the following if you did not get it off of the video: mono- = 1 di- = 2 tri- = 3 tetra- = 4 penta- = 5 hexa- = six hepa- = 7 octa- = 8 nona- = 9 deca- = 10

Copy the following if you did not get it off of the video: mono- = 1 di- = 2 tri- = 3 tetra- = 4 penta- = 5 hexa- = six hepa- = 7 octa- = 8 nona- = 9 deca- = 10

The prefix tri- means 3, so you have 3 nitrogens. The symbol for nitrogen is N. The prefix hexa means 6, so you have 6 sulfurs. The symbol for sulfur is S. Therefore the answer would be: N3S6

The prefix tri- means 3, so you have 3 nitrogens. The symbol for nitrogen is N. The prefix hexa means 6, so you have 6 sulfurs. The symbol for sulfur is S. Therefore the answer would be: N3S6

In the formula, you have 3 phosphorus atoms. The prefix for 3 is tri-. You have 5 chlorine atoms. The prefix for 5 is penta-. When you put it together: 3 phosphorus = triphosphorus and 5 chlorine atoms = pentachloride. Remember for the second nonmetal you drop the -ine and add the -ide.

 
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