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– 4x – 15 > – 2x – 11

-x< 1

5x - 10 = 5(x - 2)

5x – 3 = 12

– πx + 4π < π

π x + 4 π = π

5x – 3 ≥ 12

...

2 x – 11 = – 9

V = {3}

V = |R

V = ]3, +∞[

V = [3, +∞[

V = ]-∞, -2]

V = {1}

V = ]-1, +∞[

V = ∅

V = {-3}