– 4x – 15 > – 2x – 11
-x< 1
5x - 10 = 5(x - 2)
5x – 3 = 12
– πx + 4π < π
π x + 4 π = π
5x – 3 ≥ 12
...
2 x – 11 = – 9
V = {3}
V = |R
V = ]3, +∞[
V = [3, +∞[
V = ]-∞, -2]
V = {1}
V = ]-1, +∞[
V = ∅
V = {-3}