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Mastering SQL Aggregation Problems

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Drills to master SQL aggregation problems

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Compléter

Mastering SQL Aggregation ProblemsVersion en ligne

Drills to master SQL aggregation problems

par Good Sam
1

FROM SUM total_sales sales AS SELECT amount

Problem 1 : Total Sales
Question : You have a table sales ( order_id INT , amount DECIMAL ) . Write a SQL query to calculate the total sales amount .

Solution :

( )
;





SELECT SUM ( amount ) AS total_sales
FROM sales ;

Explanation : The SUM ( ) function aggregates the total sales by summing up all the amount values in the sales table .

2

FROM AVG SELECT average_sale_amount AS amount sales

Problem 2 : Average Sales per Order
Question : Calculate the average sales amount per order from the sales table .

Solution :

( )
;





SELECT AVG ( amount ) AS average_sale_amount
FROM sales ;

Explanation : The AVG ( ) function calculates the average amount of sales by dividing the total sum of the amount column by the count of rows ( i . e . , number of orders ) .

3

FROM order_details AS DISTINCT COUNT distinct_products SELECT product_id

Problem 3 : Count of Distinct Products Sold
Question : Given a table order_details ( order_id INT , product_id INT ) , find the number of distinct products sold .

Solution :

( )
;






SELECT COUNT ( DISTINCT product_id ) AS distinct_products
FROM order_details ;

Explanation : COUNT ( DISTINCT product_id ) counts the unique product IDs in the order_details table , ignoring duplicates .

4

MIN amount MAX max_sale FROM sales SELECT AS amount AS min_sale

Problem 4 : Maximum and Minimum Sale
Question : Find both the largest and smallest sale amounts from the sales table .

Solution :

( ) , ( )
;






SELECT MAX ( amount ) AS max_sale , MIN ( amount ) AS min_sale
FROM sales ;

Explanation : The MAX ( ) and MIN ( ) functions are used to find the highest and lowest values in the amount column of the sales table .

5

AS EXTRACT sale_date MONTH AS FROM AS total_sales YEAR sale_date sale_year SELECT SUM MONTH FROM sale_month sales FROM EXTRACT EXTRACT amount BY sale_date FROM sale_month sale_year EXTRACT BY YEAR GROUP ORDER sale_date FROM

Problem 5 : Grouped Sales by Month
Question : Assuming a table sales ( order_id INT , amount DECIMAL , sale_date DATE ) , calculate total sales for each month .

Solution :

( ) ,
( ) ,
( )

( ) , ( )
, ;











SELECT EXTRACT ( YEAR FROM sale_date ) AS sale_year ,
EXTRACT ( MONTH FROM sale_date ) AS sale_month ,
SUM ( amount ) AS total_sales
FROM sales
GROUP BY EXTRACT ( YEAR FROM sale_date ) , EXTRACT ( MONTH FROM sale_date )
ORDER BY sale_year , sale_month ;

Explanation : The SUM ( ) function is used to aggregate sales per month , grouped by year and month extracted from sale_date . The GROUP BY clause groups the data into sets that share the same year and month so that SUM ( ) can compute totals for each group .